If Vd = 50 L and CL = 5 L/h, what is the elimination half-life t1/2?

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Multiple Choice

If Vd = 50 L and CL = 5 L/h, what is the elimination half-life t1/2?

Explanation:
Elimination half-life in first-order kinetics depends on how far the drug distributes (volume of distribution) relative to how fast it is cleared (clearance). The relationship is t1/2 = 0.693 × Vd / CL. Plugging in Vd = 50 L and CL = 5 L/h gives t1/2 = 0.693 × 50 / 5 = 0.693 × 10 = 6.93 hours. So the elimination half-life is about 6.93 hours. (Doubling Vd would double t1/2; doubling CL would halve t1/2.)

Elimination half-life in first-order kinetics depends on how far the drug distributes (volume of distribution) relative to how fast it is cleared (clearance). The relationship is t1/2 = 0.693 × Vd / CL.

Plugging in Vd = 50 L and CL = 5 L/h gives t1/2 = 0.693 × 50 / 5 = 0.693 × 10 = 6.93 hours.

So the elimination half-life is about 6.93 hours. (Doubling Vd would double t1/2; doubling CL would halve t1/2.)

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